Question

A and B do a piece of work in 10 days B and C do it in 15 days and C and A do it in 12 days in how many days will each one of them finish it working alone

Answer 1

Given that A and B can do a work in 10 days.

A + B = 1/10  ------------- (1)

Given that B and C can do a work in 15 days.

B + C = 15  ---------- (2)

Given that C and A can do a work in 12 days.

C + A = 12   ----------- (3)


On Adding (1),(2),(3), we get

2(A + B + C) = 1/10 + 1/15 + 1/12

                    = 15/60

                    = 1/4


A + B + C 's 1 - day work = 1/8.


Now,

A's 1 - day work = 1/8 - 1/15
 
                           = 7/120
 
                           = ~17.


A's work = 17 days.

                          
B's 1-day work = 1/8 - 1/12

                         = 1/24.


B's work = 24 days.


C's 1-day work = 1/8 - 1/10

                         = 1/40

C's work = 40 days.


Hop this helps!

Answer 2

Hope this helps........