Math, asked by radhigaraman4638, 1 year ago

A and b do a work in 30 days b and c do a work in 24 days a and c do a work in 20 days . They all together do a work in 10 days when b and c leave .Then a takes how many days ?

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Answered by vaaruni84
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A and B can do a piece of work in 30 days, while B and C can do the same work 24 days, and A and C can do it in 20 days. They work together for 10 days before B and C leave. How many days more will A take to finish the work?

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Gauri Shanker, 96.7%iler in CAT, AIR under 100 twice in SSC CGL.

Answered Jun 14

Let the work is 120 units. #just a trick, you can assume anything #

Let a, b and c be the works done by them per day.

As per the question

a+b = 120/30 = 4 units/day.

Similarly b+c = 5

c+a = 6

Solving these, we get a= 2.5, b = 1.5, c=3.5.

In 10 days, they'll do 10*(7.5) = 75.

Remaining work = 120–75= 45

Then A will do 45 units in 45/2.5 = 18 days

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