A and b do a work with 5 days, a and c in 6 days, b and c in 20 days.if a do alone how many days it will take?
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Let A, B and C do the job alone in A , B and C number of days.
Productivity per day of A, B and C = 1/A, 1/B and 1/C respectively.
1/A + 1/B = 1/5 ---(1)
1/A + 1/C = 1/6 --- (2)
1/B + 1/C = 1/20 --- (3)
(2) - (3) => 1/A - 1/B = 7/60
Add (1) to get: 1/A = 19/120 So A = 120/19 days
Productivity per day of A, B and C = 1/A, 1/B and 1/C respectively.
1/A + 1/B = 1/5 ---(1)
1/A + 1/C = 1/6 --- (2)
1/B + 1/C = 1/20 --- (3)
(2) - (3) => 1/A - 1/B = 7/60
Add (1) to get: 1/A = 19/120 So A = 120/19 days
kvnmurty:
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