A and B doing a work 10days and 15 days respectively the work together for 5days and remaining work done by C and C takes 2 days to complete work then their total wages is 1500 then find the wages of B and C for one day
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Work done by A and B in 5- days =5/10+5/15= 25/30= 5/6.
The remaining (1–5/6)= 1/6 - part of the work is done by C- in 2-days.
So C- can complete in day = 1/(2 X6)=1/12- part of the work. The whole work can be completed by C in-12– days.
Therefore the efficiency ratio of A:B:C =1/10: 1/15: 1/12
= 6 :4 : 5
So wage of A= ₹ 1500 x 5/10= ₹ 750
Daily wage of A=₹ 750/5= ₹150
Wage of B=₹ 1500 x 5/15= ₹ 500
Daily wage of B=₹ 500/5= ₹100
Wage of C=₹ 1500 x 1/6= ₹ 250
Daily wage of C= ₹ 250/2= ₹ 125
Therefore the sum the daily of wages of B and C =(₹100+125) = ₹ 225.
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