A and B. each has certain amount (In INR). If A gives INR 80 to B, B will have 1.5 times the amount left 1210 12 with A. If B gives INR 80 to A, A will have 2 times the amount left with B. The total amount with A and B is
Answers
Answer:
A have 320
B have 280
Step-by-step explanation:
form the equation and solve it
Solution :-
Let us assume that, Initially A has INR a and B has INR b .
Case 1) :- when A gives INR 80 to B :-
→ A left amount = INR (a - 80)
→ B new amount = INR (b + 80)
A/q,
→ B new amount = 1.5 * (A left amount)
→ (b + 80) = 1.5(a - 80)
→ b + 80 = 1.5a - 120
→ 1.5a - b = 80 + 120
→ 1.5a - b = 200 ----------- Eqn.(1)
Case 2) :- when B gives INR 80 to A :-
→ B left amount = INR (b - 80)
→ A new amount = INR (a + 80)
A/q,
→ A new amount = 2 * (B left amount)
→ (a + 80) = 2(b - 80)
→ a + 80 = 2b - 160
→ 2b - a = 80 + 160
→ 2b - a = 240 ----------- Eqn.(2)
Multiply Eqn.(1) by 2 and adds result in Eqn.(2),
→ (2b - a) + 2(1.5a - b) = 240 + 2 * 200
→ 2b - 2b + 3a - a = 240 + 400
→ 2a = 640
→ a = INR 320
putting value of a in Eqn.(2),
→ 2b - 320 = 240
→ 2b = 240 + 320
→ 2b = 560
→ b = INR 280
Hence, The total amount with A and B is INR 320 and INR 280 respectively .
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