A and B each have certain no. of oranges.A says to B if u give me 10 of your oranges I will have twice the no. of oranges left with you.B replies If you give me 10 of your oranges I will have the same no. of oranges as left with you.Find the no. of oranges with A and B separately.
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A=20 ORANGES
b=10 oRANGES
b=10 oRANGES
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Let the no of oranges with 'A' and 'B' equal to X and Y respectively
Then,according to your question Y gives 10 oranges to X,then X will have twice the number of oranges left with Y
Written numerically =>
X + 10 = 2(Y - 10)
And if X gives 10 oranges to Y,then Y will have the same number of oranges as X (is left with)
Written numerically=>
Y + 10 = X - 10 =>
Y + 10 + 10 = X
X = Y + 20
Taking the previous equation and substituting the values(of X),we get
X + 10 = 2(Y - 10) =>
(Y + 20) + 10 = 2Y -20 =>
Y + 30 = 2Y - 20
30 + 20 = 2Y - Y
50 = Y
Taking one of the preceding equations.
X = Y + 20
X = 50 + 20
X = 70
Hence,A has 70 oranges whereas B has 50 oranges.
Then,according to your question Y gives 10 oranges to X,then X will have twice the number of oranges left with Y
Written numerically =>
X + 10 = 2(Y - 10)
And if X gives 10 oranges to Y,then Y will have the same number of oranges as X (is left with)
Written numerically=>
Y + 10 = X - 10 =>
Y + 10 + 10 = X
X = Y + 20
Taking the previous equation and substituting the values(of X),we get
X + 10 = 2(Y - 10) =>
(Y + 20) + 10 = 2Y -20 =>
Y + 30 = 2Y - 20
30 + 20 = 2Y - Y
50 = Y
Taking one of the preceding equations.
X = Y + 20
X = 50 + 20
X = 70
Hence,A has 70 oranges whereas B has 50 oranges.
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