Question

A and b have 460 coins altogether. if 3/4 of a's no.of coins is equal to 2/5 of b's no.of coins must b give to a so that both have equal no. of coins

Answer 1

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Answer 2

$a + b = 460 \: equation \: (1) \\ \frac{3}{4} \times a = \frac{2}{5} \times b \\ \frac{a}{b} = \frac{8}{15} \\ \\ put \: value \: of \: a \: and \: b \: in \: equation \: 1 \\ 8x + 15x = 460 \\ 23x = 460 \\ x = 20 \\ a = 160 \: \: \: b = 300 \\ then \: b \: have \: to \: give \: 70 \: coins \: then \: each \: of \: them \: have \: 230 \: coins$