Question

A and B have a certain number of mangoes. A say to B,“if you give me 30 of your mangoes, I will have twice as many as left with you.” B replies,“if you give me 10 of your mangoes, I will have thrice as many as left with you.” How mangoes does each have?




Please give written solution

Answer 1

Let A and B have x and y mangoes respectively.

if A gets 30 mangoes A will have x + 30 mangoes and B will have y - 30 

according, to the problem, x + 30 = 2(y - 30)

            or, x + 30 = 2y - 60

            or, x - 2y = -90 .......................(i)

Also,        3(x - 10) = y + 10

                or,3x - 30 = y + 10

              or, 3x - y =40 .......................(ii)

Solving eqn(i) and eqn(ii) we get x = 34 and y = 62

So A and B has 34 and 62 mangoes initially.

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Answer 2

hey mate❤️

your answer:-

Let A and B have x and y mangoes respectively.

if A gets 30 mangoes A will have x + 30 mangoes and B will have y - 30 

according, to the problem, x + 30 = 2(y - 30)

                                      or, x + 30 = 2y - 60

                                      or, x - 2y = -90 .......................(i)

Also,                                  3(x - 10) = y + 10

                                      or,3x - 30 = y + 10

                                      or, 3x - y = 40 .........................(ii)

Solving eqn(i) and eqn(ii) we get x = 34 and y = 62

So A and B has 34 and 62 mangoes initially.