Question

A and b have monthly income in ratio 5:6 and monthly expenditure in ratio 3:4 . If they save rs 1800 and 1600 respectively, find monthly income of b

Answer 1

HEY DEAR ... ✌

____________________________


Incomes of A and B=5x and 6x and expenses of A and B = 3y and 4y

? Then, savings of A = 5x-3y = 1800---?(1)

Savings of B = 6x-4y = 1600---?(2)

By solving equations (1) and (2)

y = 1400

? Monthly income of B = Expenses of B + savings of B

= 4y+1600 = 4(1400) + 1600 = Rs.7200

HOPE , IT HELPS ... ✌

Answer 2

Answer:

$\boxed{\setlength{\unitlength}{.8mm}\begin{picture}(55,25)\thicklines\put(35,18){\vector(2,-1){20}}\put(20,18){\vector(-2,-1){20}}\put(17,21){\sf\large\underline{\bigstar \:Income}}\put(0,1){\sf{Expense}}\put(25,1){+}\put(43,1){\sf{Saving}}\end{picture}}$

$\sf\qquad\qquad A\qquad\qquad B\\\sf Income\quad\:\!5\:\quad\:\::\:\quad\:\:6\\\sf Expense\:\:\:3\quad\:\:\::\quad\:\:\:4\\\sf Saving\quad Rs.1800\:\quad\:Rs.1600$

$\rule{160}{1}$

Let Income of A & B be 5x and 6x.

$\underline{\bigstar\:\:\textsf{According to the Question :}}$

$\dashrightarrow\tt\:\:\dfrac{A(Income-Saving)}{B(Income-Saving)}=\dfrac{A\: Expense}{B\: Expense}\\\\\\\dashrightarrow\tt\:\:\dfrac{(5x - 1800)}{(6x - 1600)} = \dfrac{3}{4}\\\\{\scriptsize\qquad\bf{\dag}\:\:\textsf{By Cross Multiplication :}}\\\\\dashrightarrow\tt\:\:4(5x - 1800) =3(6x - 1600)\\\\\\\dashrightarrow\tt\:\:20x - 7200 =18x - 4800\\\\\\\dashrightarrow\tt\:\:20x - 18x =7200 - 4800\\\\\\\dashrightarrow\tt\:\:2x =2400\\\\\\\dashrightarrow\tt\:\:x = \dfrac{2400}{2}\\\\\\\dashrightarrow\tt\:\:x =Rs. \:1200$

$\rule{200}{2}$

$\underline{\bigstar\:\:\textsf{Monthly Income of B :}}$

$:\implies\tt Monthly\:Income\:of\:B=6x\\\\\\:\implies\tt Monthly\:Income\:of\:B=6 \times Rs.\:1200\\\\\\:\implies\underline{\boxed{\textsf{\textbf{Monthly Income of B = Rs. 7200}}}}$