Question

A and B have Rs.28 between them; A gives Rs.3 to B and then finds he has six times as much money as B; how much each had at first?

Answer 1

Answer:

B=2 and A=30

Step-by-step explanation:

ATQ

A gives 3 to B then also it is 6 times than B it means

A=6(B+3) (I)

Now as we know that

A-B=28. (GIVEN)

6(B+3) -B=28.

( REPLACING A FROM EQUATION I)

=>6B+18-B=28

=> 5B=10

=>B=2

PUTTING THE VALUE OF B IN EQUATION I WE GET

A=30