A and B have some money with them. A said to B if you give me 100 my money will become 75% of your money B said to A instead you give me 100 your money will become40% of my money how much money did A and B have originally
Answers
Answered by
125
As per 1st condition: (A + 100) = 0.75(B - 100)
This gives us the value of A = 0.75B - 175 -------------- (i)
As per the 2ns condition: (A - 100) = 0.40(B + 100)
This gives us the value of A = 0.40B + 140 -------------- (ii)
Equating (i) and (ii), we get B = 900
Inputting this value in (i), we get the value of A = 500
So originally, A had Rs. 500 and B had Rs. 900
This gives us the value of A = 0.75B - 175 -------------- (i)
As per the 2ns condition: (A - 100) = 0.40(B + 100)
This gives us the value of A = 0.40B + 140 -------------- (ii)
Equating (i) and (ii), we get B = 900
Inputting this value in (i), we get the value of A = 500
So originally, A had Rs. 500 and B had Rs. 900
Answered by
128
Amount of Money with A = X
Amount of Money with B = Y
(X + 100) = 75/100 * (Y - 100) => 3 Y - 4 X = 700 --(1)
(X - 100) = 40/100 * (Y + 100) => 5 X - 2 Y = 700 -- (2)
(1) * 2 + (2)*3 gives 7 X = 3500 => X = 500
Substituting in (1) => Y = 2700/3 = 900
Amount of Money with B = Y
(X + 100) = 75/100 * (Y - 100) => 3 Y - 4 X = 700 --(1)
(X - 100) = 40/100 * (Y + 100) => 5 X - 2 Y = 700 -- (2)
(1) * 2 + (2)*3 gives 7 X = 3500 => X = 500
Substituting in (1) => Y = 2700/3 = 900
Similar questions