A and B have some oranges. If A gives 2 oranges
to B. A will have the oranges half of B. IF B gives
10 oranges to A, the number of oranges of A and B
will be reversed. A and B have number of oranges
respectively
(a) 26, 14
(b) 13,26
(c) 16.26
(d) 25, 14
Answers
Answered by
0
Answer:
A had 16 oranges and B had 26 oranges.
Option (c) is correct.
Step-by-step explanation:
Let A have x oranges and B have y oranges.
Now,
If A gives 2 oranges to B,
A will have (x - 2) oranges and B will have (y + 2) oranges.
Then, according to the Question,
A = (1/2)B {After giving 2 oranges}
(x - 2) = (1/2)(y - 2)
2(x - 2) = y + 2
2x - 4 = y + 2
2x - 4 + 2 = y
2x - 6 = y
y = 2x - 6 ----- 1
But,
according to the Question,
A's oranges = B's oranges - 10
x = (y - 10)
x + 10 = y
But from eq.1 we get,
x + 10 = 2x - 6
2x - x = 10 + 6
x = 16
The putting x = 16, in eq.1 we get
y = 2(16) - 6
y = 32 - 6
y = 26
Hence,
A had 16 oranges and B had 26 oranges.
Hope it helped and believing you understood it....All the best
Similar questions