Question

A and B individualy can do a work in 6 days and 12 days respectively. A worked for first 2 days and then left. In how many days will B finish the remaining part of the work?​

Answer 1

Answer:

A left his work for = 4 days

B's speed is 2 times less than that of A

so A's work done by B was in (4*2)days = 8 days

B completed the work in (12+8)days =20 days

.

Ans.) B completed the work in 20 days.

Answer 2

Step-by-step explanation:

in 20 days............................