A and B left kanpur simultaneously and travelled Lucknow.A speed was 20km/h and B speed was 12km/h.3 hours later C left kanpur and travelled in the same direction.after some time he overtook B and 120 minutes further he overtook A.find speed of C
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Answer:
37.62
Step-by-step explanation:
let say after x hrs C overtook B
and speed of C = C km/hr
distance covered by C = Cx km
distance covered by b =12×(3+x)
= 36+12x
Cx = 36 + 12x
after 120 mins , 2hrs more C overtook A
distance covered by C
=C (x+2) km
distance covered by A =20(x + 5) km
CX + 2C = 20x + 100
2C = 8x + 64
C = 4x + 32
(4x+32)x = 36 + 12x
(x +8)x = 9 + 3x
x^2 +5x - 9=0
x =1.405
C =37.62 km
speed of C =37.62 km/hr
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