Math, asked by arusin, 4 months ago

A and B play a game.
First A chooses a sequence of three tosses of a coin and share it with B; then B chooses a different sequence of three tosses and share it with A. Then they throw a fair coin repeatedly until one sequence or the other shows up as three consecutive tosses.
For instance, A might choose (head, tail, head); then B might choose (tail, head, tail). If the sequence of tosses is (head, tail, tail, head, tail), B would win.
If both players play rationally (make their best possible choice), what is the probability that A wins?


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Answers

Answered by rrupeshkumargupta24
0

Answer:

(tail ,head ,head, tail,head

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