Question

A and B play throwing 3 coins each. A wins if the number
of heads is same in the throws of both A and B. The
probability of winning A is
(a) 5/16 (b) 19/64 (c) 7/8 (d) None​

Answer 1

Answer:

C) 7/8

Step-by-step explanation:

p (a)=n (a)/n(s)

=7/8

Answer 2

Answer:

A and B are independent so, event perform is also independent.

Since, we have 3 coins and we have to find same number of head

Step-by-step explanation:

case 1: Both got one head (Select 1 head from 3 outcomes)

³C₁ x ³C₁ = 3 x 3 = 9

case 2: Both got 2 head (Select 2 head from 3 outcomes)

³C₂ x ³C₂ = 3 x 3 = 9

case 3: Both got 3 head (select 3 head from 3 outcomes)

³C₃ x ³C₃ = 1 x 1 = 1

Now, Since 1 coin has 2 outcomes so, 6 coins (3 from A 3 from B) = 2⁶ (outcomes)

so, ans: ( 9 + 9 + 1) / 2⁶ = 19 / 64