A and B play throwing 3 coins each. A wins if the number
of heads is same in the throws of both A and B. The
probability of winning A is
(a) 5/16 (b) 19/64 (c) 7/8 (d) None
Answers
Answered by
0
Answer:
C) 7/8
Step-by-step explanation:
p (a)=n (a)/n(s)
=7/8
Answered by
0
Answer:
A and B are independent so, event perform is also independent.
Since, we have 3 coins and we have to find same number of head
Step-by-step explanation:
case 1: Both got one head (Select 1 head from 3 outcomes)
³C₁ x ³C₁ = 3 x 3 = 9
case 2: Both got 2 head (Select 2 head from 3 outcomes)
³C₂ x ³C₂ = 3 x 3 = 9
case 3: Both got 3 head (select 3 head from 3 outcomes)
³C₃ x ³C₃ = 1 x 1 = 1
Now, Since 1 coin has 2 outcomes so, 6 coins (3 from A 3 from B) = 2⁶ (outcomes)
so, ans: ( 9 + 9 + 1) / 2⁶ = 19 / 64
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