A and b rent a pasture for 10 months. A puts in 100 cows for 8 months .How many cows can b put in for the remaining 2 months ,if he pays 3/2 as much as a
Answers
Answer:
600 cows
Step-by-step explanation:
From the statement 3/2 times as much as a it means :
B = 3/2A
Let the amount paid by A be t then the amount paid by B is :
B = 3/2t
The ratio of price paid by A to B is :
t/(3/2t) = 2/3 = 2 : 3
The ratio of the prices A : B = 2:3
We have the specifications for A:
Cows = 100
Months = 8 months
Cow months = 100 × 8 = 800
Let the number of cows that B has be x then:.
Cow months = x × 2 = 2x
The ratio of the Cow months is :
800 : 2x
This ratio is equal to the ratio of the prices.
Therefore :
800/2x = 2/3
3(800) = 2(2x)
2400 = 4x
x = 2400/4
x = 600
Therefore B puts 600 cows.
Answer:
Step-by-step explanation:
Simplest method solve this sort of question is as follows:
Given that:
B pays 3/2 of A
Hence, B = 3A/2
Or, A/B = 2/3
Or, A:B = 2:3
100cows × 8 months. 2
----------------------------. = -------
x cows × 2 months. 3
800 2
------. =. -------
2x. 3
2400. =. 4x
x. =. 600. Cows ✓
And that's the answer.