Question

A and B represent digit's in the addition shown below. find the value of A times B. BAB, ABB, +ABB. ​

Answer 1

Answer:

Given : two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.

To find : the two numbers

Let x and y be the two numbers required.

According to the question :

⇒2x+3y=92 ........(1)

⇒4x−7y=2 ........(2)

multiply the first equation by 2 , and subtract eqn (1) from eqn (2)

4x+6y=184

−(4x−7y=2) , we get

⇒13y=182

⇒y=13182=14

Put y=14 in (1)

2x+3y=92

⇒2x+3×14=92

⇒2x=92−42=50

∴x=250=25

∴x=25 and y=14