A and B separately can complete a work in 18 days and 24 days respectively. They both started working and after 4 days A left the work. Remaining work B can complete with the help of C in 5 days. If they get total wages 2880. Then wages of C is?
Answers
Given:
A takes 18 days to do a work
B takes 24 days to do a work
They both started working and after 4 days.
A left the work
B completes the remaining work with the help of C in 5 days.
Total wages= 2880
To find:
Wages of C
Solution:
By LCM method, total work is determined
We find the LCM of 18 and 24 to determine the total work, which is 72
Efficiency(work done in 1 day) of A= 4
Efficiency(work done in 1 day) of B= 3
Work done by A and B in the first 4 days= (4+3)*4= 28
So, remaining work= 72-28= 44
Let the efficiency of C be x
Remaining work is done by B and C in 5 days
So we can write-
(3+x)* 5= 44
x= 29/5 or 5.8
To calculate the wages, we need to find the ratio of work done by the three
Work done by A= 4*4= 16
Work done by B = 9*3= 27
Work done by C = 5*5.8 = 29
The work ratio= 16:27:29
Wage of C = (29/72)* 2880 = Rs. 1160
The wages of C is Rs. 1160.