A and B start from the same point and cover equal distances. A travels by car and covers the distance
in 3 hours with a speed of 50 kmph. B travels by a bus which stops for 10 minutes after covering 10 km. In
how much time will the bus reach the destination, if the speed of the bus is 40% less than the car. A. 7 h 20 min
B. 7 h 30 min
C. 7 h
D. 6 h 40 min
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Answer:
7hr 20 min
Step-by-step explanation:
distance=speed×time
total distance =50km×3hr= 150km
speed of bus is
50 - 40% of 50 = 30km/hr
time taken by bus without stopping
150/30 =5hr
since bus stops for 10 min at each 10km
150km/10km = 15 stops
but last stop we are not considering
because its the destination.
14 stops ×10 min =140 min
so total time spent will be 5hr + 140min ie,
7hr 20min
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