Question

A and B started a business with initial investments in the respective ratio of 18 : 7 .After four months from the start of the business, A invested $ 2000 more and B invested $ 7000 more. At the end of one year, if the profit was distributed among them in the ratio of 2 : 1 respectively, what was the total initial investment with which A and B started the business?​

Answer 1

A's initial investment = RS.18x B's initial investment = Rs.7x According to the question,

18x x 4 + (18x + 2000) x 8 / 7x x 4 + (7x + 7000) x 8

= 2/1

=> 18x x 4 + (18x + 2000)x2 /

7x x 4 + (7x + 7000) x 8

= 2/1

=> 18x + 36x + 4000

= 14x + 28x + 28000

=> 54x - 42x = 28000 - 4000

=> 12x = 24000

=> x=24000/12 = 2000

Total initial investment of A and B = 25x

= 25 x 2000

= Rs.50000

Answer 2

ANSWER:-

Given:

A & B started a business with initial investment in the respective ratio of 18:7.After Four month from the start of the business, A invested Rs.2000 more B invested Rs.7000 more. At the end of one year, if the profit was distributed Among them in the ratio of 2:1 respectively.

To find:

What was the total initial investment with which A & B started the business?

Solution:

Let A= 18x & B= 7x

$= > (18x \times 4) + (18x + 2000) 8 \ratio (7x \times 4) + (7x + 7000)8 = 2 \ratio 1 \\ \\ = >18x + (18x + 2000)2 \ratio (7x) + (7x + 7000)2 = 2 \ratio 1 \\ \\ = > 18x + 36x + 4000 \ratio 7x + 14x + 14000 = 2 \ratio 1 \\ \\ = > 54x + 4000 \ratio 21x + 14000 = 2 \ratio 1 \\ \\ = > \frac{54x + 4000}{21x + 14000} = \frac{2}{1} \\ \\ = > \frac{27x + 2000}{21x + 14000} = \frac{1}{1} \\ \\ = > 27x + 2000 = 21x + 14000 \\ \\ = > 27x - 21x = 14000 - 2000 \\ \\ = > 6x = 12000 \\ \\ = > x = \frac{12000}{6} \\ \\ = > x = rs.2000$

Now,

A = 18x = 18× 2000

A= Rs.36000

&

B= 7x = 7× 2000

B= Rs.14000

Therefore,

Total initial investment with A& B started the business ;

A + B

=) Rs. 36000 + Rs.14000

=) Rs.50000

Hope it helps ☺️