a and b started a work together but b left after 12days. the remaining 2/3rd work is completed by A along with c in 20days. if A alone can complete the whole work in 60days, then in how many days A, B, and C together can complete the work?
Answers
Answer:B
Step-by-step explanation:Let the total unit of work be 6 units (LCM of 2 and 3)
(A+B)do=
3
6
=2 units/day
(A+B)
′
s2 day work =2×2=4 units
Work left =6−4=2 units
This remaining work is done by A in 2 days.
∴A
′
s per day work =
2
2
=1 unit/day
∴B
′
s per unit work =(A+B)
′
s work−A
′
s work
=2−1=1 unit/day
B alone can complete the work in =
1
6
=6 days.
Answer:
22 1/2 days
Step-by-step explanation:
Given,
a and b started a work together but b left after 12days.
let x be days A+B worked together
A+B=1/x days
after 12 days B left,A+b worked for 12 days
A+B=12/x
the remaining 2/3rd work is completed by A along with c in 20 days.
if the remaining work is 2/3 then work done be 1-2/3=1/3
1/3 work done by A+B in 12/x days
1/3=12/x days
x=36 days
A+B=1/36 days
if A alone can complete the whole work in 60 days,
A=1/60
B=1/36-A
B=1/36-1/60
B=5-3/180
B=2/180
B=1/90 days
the remaining 2/3rd work is completed by A along with c in 20 days.
2/3 work in 20 days done by A+C
let x be individual days for C
2/3=(A+C)*20
2/3=(1/60+1/x)*20
2/3(60*x)/60+x=20
2x=60+x
x=60 days
C=1/60 days
A+B+C=1/60+1/90+1/60
A+B+C=6+4+6/360
A+B+C=16/360
A+B+C=22 1/2