A and B started towards each other simultaneously with velocities 30 kmph and 50 kmph respectively. If they meet each other after 45 minutes, what would be
the distance between A and B when they started?
Ops: A. 30 km
B. 60 km
C. 75 km
D. 45 km
Answers
Answer
60
step by step:
per one hour they travel 80km
then 45 mins they travel = (80/60)*45
Answer:
The correct answer is B) 60 km.
If A and B meet each other after 45 minutes, the distance between them when they got started would be 60 km.
Step-by-step explanation:
Given :
- A and B simultaneously began moving in opposite directions at speeds of 30 and 50 kilometres per hour.
- After 45 minutes, they finally cross paths.
To find :
- The separation between A and B at the beginning.
Solution :
A and B are shown to be approaching one another. They therefore move in the obverse directions.
We are aware that distance = velocity x time and velocity = distance/time.
‘A’ travels a distance of 30 km in an hour at a speed of 30 kmph.
So in 45 mins = (45/60) hours, additionally A covers a distance of = 30 x (45/60) = 22.5 km
Therefore we can say that A covers a distance of 22.5 km in 45 minutes.
The velocity of B= 50 kmph
= which is ; A covers a distance of 50 km in 1 hour
Hence in 45 mins = (45/60) hours, 5 covers a distance of = 50 x (45/60) = 37.5 km.
Furthermore, B covers a distance of 37.5 km in 45 minutes.
A and B are moving apart because they are going in different directions.
the sum of the distances they would have travelled in 45 minutes from when they started (When they first meet).
A and B are separated by 22.5 + 37.5, which equals 60.
When they first started, A and B were separated by 60 miles.
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