A and b started towards each other simultaneously with velocities 30 kmph and 50 kmph respectively. If they meet each other after 45 minutes. What would be the distance between a and b when they started?
Answers
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GIVEN :
=> A AND B STARTED TRAVELLING TOWORDS EACHOTHER ......
=> AFTER 45 MIN. THEY MEET
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VELOCITY OF A :
=> 30 KMPH
VELOCITY OF B :
=> 50 KMPH
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TIME :
=> 45 MIN
=> 45 / 60
=> 3 / 4 HR
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A WILL COVER THE DISTANCE
=> 30KM * 3/4 HR
=> 22.5 KM
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B WILL COVER THE DISTANCE :
=> 50 * 3/4 HR
=> 36.5 KM
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DISTANCE THEY COVER TOGETHER :
=> DISTANCE BY A + DISTANCE BY B
=> 22.5 + 36.5
=> 59 KM
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=> DISTANCE BETWEEN THEM IS 59 KM ...
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HOPE IT WILL HELP U......
THANKS AGAIN.....
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The distance between A and B when they started is 60 km.
Given:
A and B started towards each other simultaneously with velocities
30 kmph and 50 kmph respectively.
They meet each other after 45 minutes.
To Find:
The distance between A and B when they started.
Solution:
We are given that A and B are moving towards each other. Hence, they move in opposite directions.
We know that
velocity = distance/ time
⇒ distance = velocity x time.
The velocity of A = 30 kmph
⇒ A covers a distance of 30 km in 1 hour.
Hence in 45 mins = (45/60) hours, A covers a distance of = 30 x (45/60) = 22.5 km
∴ A covers a distance of 22.5 km in 45 minutes.
The velocity of B = 50 kmph
⇒ A covers a distance of 50 km in 1 hour.
Hence in 45 mins = (45/60) hours, 5 covers a distance of = 50 x (45/60) = 37.5 km.
∴ B covers a distance of 37.5 km in 45 minutes.
Since A and B are traveling in opposite directions, the distance between them when they started would simply be the sum of their distances covered in 45 minutes (when they meet each other).
⇒ Distance between A and B = 22.5 + 37.5 = 60
∴ The distance between a and b when they started is 60 km.
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