a and b tap can fill a tank respectively in 12 min and 15 min. both the taps are open. after 3 min a tap stopped. remaining tank to fill how much time to take?
Answers
Answered by
0
Answer:
A's one minute work = 1/12
B's one minute work = 1/15
Both working together = A's work +B's work
= 1/12 + 1/15
= 5/60 + 4 /60
= 9/60
= 3/20
Total work is 1
A and B's 3 minute work = 3 + 3/20
= 60/20 + 3/20
= 63/20
work done = 20 / 63
work remaining = 1 - 20/63
= 43 / 63
time taken do 43/63 work = (43/63) / (20 / 63)
= 43/63 X 63/20
= 43 /20
= 2.15 minutes
= 2 minutes and 25 seconds
it will take 2 minutes and 25 seconds to fill .
Similar questions