A and B throw a pair of dice alternately. A wins the game if he gets a total of 7 and B wins the game if he gets a total of 10. If A starts the game, then find the probability that B wins.
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A wins if:(1,6);(2,5);(3,4);(4,3);(5,2);(6,1)
>N(A)=6
B wins if :(4,6);(5,5);(6,4)
>N(B)= 3
Therefore the sample space for this event will be : N(A)+N(B)=6+3=9
And the probability of B winning =N(B)/sample space
=3/9=0.33
>33%
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