Question

A and B throw a pair of dice. If A throws 9, find B’s chance of throwing a higher number

Answer 1

Answer:

the probability of getting the total of numbers on the dice greater than 9 = 6/36 = 1/6

Step-by-step explanation:

Solution⤵️

Given A pair of dice is thrown

✔️Required to find: Probability that the total of numbers on the dice is greater than 9

✔️First let’s write the all possible events that can occur

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6),

It’s seen that the total number of events is 62 = 36

Favourable events i.e. getting the total of numbers on the dice greater than 9 are

(5,5), (5,6), (6,4), (4,6), (6,5) and (6,6).

✔️So, the total number of favourable events i.e. getting the total of numbers on the dice greater than 9 is 6

✔️We know that, Probability = = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of getting the total of numbers on the dice greater than 9 = 6/36 = 1/6

${}$

Answer 2

Answer:

A and B throw a pair of dice. If A throws 9, find B’s chance of throwing a higher number.

thanks

mark as brainlist answer please