Question

A and B throw a pair of dice. if A throws 9, find B's chance of throwing a higher number. ​

Answer 1

here's a detailed answer

I hope u get it

the probability is 19/36

Answer 2

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Hello mate,

Here is your answer,

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Probability=Favourable outcomes/Totaloutcomes.

Total outcomes of a pair of dice is =6×6=36

Sample space=

<= (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6). =>

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Given:- that A throws 9 from pair of dice

To find:- B's chance of throwing a higher number

<<==Solution==>>

Chances that throwing a higher number than 9 is

(4,6)(5,5)(5,6)(6,4)(6,5)(6,6)

So, P=6/36=1/6

ANSWER IS

$\frac{1}{6}$

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