A and b throw with two dice ; if a throws 9 ,then b's chance of throwing a higher no. equals
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chance to throw higher like 10 11 12
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total probability of experiments will be 36 for 2 dice.
Sample space :
{ (1,1),(1,2),.......,(6,5) }
therefore, there will be 6 outcomes that are higher than 9.
which are : { (4,6),(5,5),(5,6),(6,4),(6,5),(6,6) }
P(E) = no. of favorable o.c./total o.c.
= 6/36
= 1/6
o.c. = outcomes
Sample space :
{ (1,1),(1,2),.......,(6,5) }
therefore, there will be 6 outcomes that are higher than 9.
which are : { (4,6),(5,5),(5,6),(6,4),(6,5),(6,6) }
P(E) = no. of favorable o.c./total o.c.
= 6/36
= 1/6
o.c. = outcomes
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