Question

A and b together can complete a particular task in 4 days. If a alone can complete the same task in 6 days, how many days will b take to complete the task if he works alone?

Answer 1

Answer:

$\bold{12\ days}$

Step-by-step explanation:

$Part\ of\ the\ task\ A\ and\ B\ together\ can\ complete\ in\ 1\ day = \frac{1}{4} \\ \\ Part\ of\ the\ task\ A\ alone\ can\ complete\ in\ 1\ day = \frac{1}{6} \\ \\ \\ Part\ of\ the\ task\ B\ alone\ can\ complete\ in\ 1\ day\\ \\ = \frac{1}{4} - \frac{1}{6} = \frac{6 - 4}{6 \times 4} = \frac{2}{24} = \bold{\frac{1}{12}} \\ \\ \\ \therefore\ B\ alone\ can\ complete\ the\ task\ in\ \bold{12\ days}.$

$\\ \\ \\ Thank\ you. \\ \\ \\ \#adithyasajeevan$

Answer 2

The number of days required by B to complete the work alone is 12 days.

• A and B can complete a task in 4 days.

Therefore, part of the task A and B can do in one day is 1/4.

• A alone can do a piece of work in 6 days.

Work done by A alone in one day is 1/6.

• Let number of days required for B to complete the work alone be x days.

Work done by B alone in one day is 1/x.

• Therefore, work done by both of them together in one day is equal to sum of both A and B working alone in one day.

1/4 = 1/6 + 1/x

1/x = 1/4 - 1/6

1/x = 2/24

x = 12

• The number of days required for B to complete the work lone be 12 days.