A and b together can complete a piece of work in 18 days, b and c in 24 days and a and c in 36 days. In how many days, will all of them together complete the work?
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given in question,
A+B. = in 18 days
B+C = in 24 days
C+A= in 36 days
LCM of 18,24,36. = 72
so, we can take total work =72
now, efficiency of,
A+B= 72/18 = 4
B+C=72/24= 3
C+A= 72/36= 2
So, the efficiency of
A+B+C= 9/2
so, work done by A, B and C together,
=( total work)/ efficiency
= 72/(9/2)
= 16 days
so, your answer is 16 days
A+B. = in 18 days
B+C = in 24 days
C+A= in 36 days
LCM of 18,24,36. = 72
so, we can take total work =72
now, efficiency of,
A+B= 72/18 = 4
B+C=72/24= 3
C+A= 72/36= 2
So, the efficiency of
A+B+C= 9/2
so, work done by A, B and C together,
=( total work)/ efficiency
= 72/(9/2)
= 16 days
so, your answer is 16 days
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