Question

A and B together can complete a piece of work in 36 days but the efficiency of B is 33 1/3% less
efficiency of A. Find in how many days 'B'alone can complete the whole work?


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Answer 1

$\huge\mathfrak\purple{Solution:-}$

★ Answer:-

→ 29 days.

★ Step-by-step explanation:-

→ A can do a job in 36 days.

B is 33.33% more efficient than A.

A’s 33.33% is=36/3

=12

B can do the same job in=36–12

=24 days.

If they do work alone in alternate days starting from A.

LCM of 36 and 24 is 72.

72/36=2

72/24=3

A+B’s two day work is =2+3

=5 work.

Total time=72/5(remaining 2)

=14*2

=28 days(remaining 2).

A=2/2

=1 day.

Total days=28+1

=29 days.

A and B finish the work to do alone with alternate days is 29 days.

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I hope this helps! :)

Answer 2

Answer:

90

Step-by-step explanation:

let A is 100X

B is 100/3 is less than A

so B is 100X - 100X/3

= 200/3

ratio of A and B is 3 : 2

A and B work 36 days

total work 36 x 5x

and b can do alone work

= 180x/2x

= 90 days

i hope you understand