a and b together can complete a piece of work in 4 days. if a alone can complete the same work in 12 days in how many days can b alone complete that work? solve
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The parallel formula is
(AB/(A+B))=4
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→work done by both a and b= 4
→work done by both in one day= 1/4
→same piece of work done by a alone = 12
→work done by a in one day= 1/12
now,
→ let work done by b in one day be x
→work done by both in one day
→1/12 + x = 1/4
→x= 1/4-1/12
→x= 1/6 ( b's day's work )
★ therefore, b alone can do the same piece of work in 6 days.
→work done by both in one day= 1/4
→same piece of work done by a alone = 12
→work done by a in one day= 1/12
now,
→ let work done by b in one day be x
→work done by both in one day
→1/12 + x = 1/4
→x= 1/4-1/12
→x= 1/6 ( b's day's work )
★ therefore, b alone can do the same piece of work in 6 days.
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