A and B together can complete a work in 10 days. They started together but A left after 2 days and the remaining work was completed by B in 12 days. In how many days can A complete the entire work while working alone?
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Answer:
6 days
Step-by-step explanation:
(A+B)'s one day's work =
1313
part
(A+B) works 2 days together =
2323
part
Remaining work =
1−231−23
=
1313
part
1313
part of work is completed by A in two days
Hence, one day's work of A =
1616
Then, one day's work of B =
13−1613−16
=
1616
So, B alone can complete the whole work in 6 days.
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