A and B together can complete a work in 24 hours, B and C together in 30 hours and C and A together in 40 hours. In how many hours C alone can do 60% of that work?
Answers
Answer:
72 hours
Given:
A and B together can complete work = 24 days
B and C together can complete work = 30 days
C and A together can complete work = 40 days
Formula used:
Work done = Time × Efficiency
Calculation:
Let total work be LCM (24, 30 and 40) = 120
A and B efficiency = 120/24 = 5
B and C efficiency = 120/30 = 4
C and A efficiency = 120/40 = 3
A, B and C efficiency = (5 + 4 + 3)/2 = 6
C's efficeiecy = 6 - 5 = 1
60% of the work completed in
(120/1) × (60/100) = 72 hours
∴ C will complete 60% of the work in 72 hours
Hope you have solved your problem
Given : A and B together can complete a work in 24 hours, B and C together in 30 hours and C and A together in 40 hours.
To Find : In how many hours C alone can do 60% of that work
Solution:
A and B together can complete a work in 24 hours
1/A + 1/B = 1/24 Eq1
B and C together in 30 hours
1/B + 1/C = 1/30 Eq2
C and A together in 40 hours.
1/A + 1/C = 1/40 Eq3
Eq3 + Eq2 - Eq1
=> 2/C = 1/40 + 1/30 - 1/24
=> 2/C = ( 3 + 4 - 5)/120
=> 2/C = 2/120
=> C = 120
Can complete 100 % work in 120 hours
=> 60 % work can be done in (60/100)120 = 72 hours
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