A and b together can complete a work in 3 days. They start together but after 2 days, b left the work. If the work is completed after two more days, b alone could do the work in
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b do that work in 6 days.
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Let the total unit of work be 6 units (LCM of 2 and 3)
(A+B)do= 6/3=2 units/day
(A+B) ′s2 day work =2×2=4 units
Work left =6−4=2 units
This remaining work is done by A in 2 days.
∴A′s per day work = 2/2=1 unit/day
∴B′s per unit work =(A+B)′s work−A′s work
=2−1=1 unit/day
B alone can complete the work in =6/1= 6 days.
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