Question

A and B together can complete a work in
3 days. They start together but after 2 days, B
left the work. If the work is completed after
two more days, B alone could do the work in
​

Answer 1

Answer:

1st Method:

(A+B)'s one day's work = 1/3 part;

(A+B) works 2 days together = 2/3 part;

Remaining work = 1-(2/3) = 1/3 part;

1/3 part of work is completed by A in two days;

Hence, one day's work of A = 1/6;

Then, one day's work of B = 1/3-1/6=1/6;

So, B alone can complete the whole work in 6 days.

2nd method:

(A+B)'s one day's % work = 100/3 = 33.3%

Work completed in 2 days = 66.6%

Remaining work = 33.4%;

One day's % work of A = 33.4/2 = 16.7%;

One day's work of B = 33.3 - 16.7 = 16.7%;

B alone can complete the work in,

= 100/16.7 = 6 days.

Answer 2

Answer:

6 days

Step-by-step explanation:

(A + B) ×3 = B×2 + 4 × A

A worked for (2+2 = 4days ) & B Worked for 2 days .

3A + 3B = 2B + 4A => A = B => A/B = 1/1

T.W = (1+1)×3 =6 units

B alone = 6/1 = 6 days