A and B together can complete a work in 3
days. They start together. But, after 2 days,
B left the work. If the work is completed after
2 more days, B alone could do the work in
(S.S.C. 2007)
Answers
Answered by
0
Answer:
6 days
Step-by-step explanation:
(A+B)'s one day's work = 13
part
(A+B) works 2 days together = 23
part
Remaining work = 1−23
= 13
part
13
part of work is completed by A in two days
Hence, one day's work of A = 16
Then, one day's work of B = 13−16
= 16
So, B alone can complete the whole work in 6 days.
Answered by
0
Answer:
6 days
Step-by-step explanation:
6 days
Let the total unit of work be 6 units (LCM of 2 and 3)
(A+B)do=36=2 units/day
(A+B)′s2 day work =2×2=4 units
Work left =6−4=2 units
This remaining work is done by A in 2 days.
∴A′s per day work =22=1 unit/day
∴B′s per unit work =(A+B)′s work−A′s work
=2−1=1 unit/day
B alone can complete the work in =16=6 days.
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