A and b together can complete a work in 4 days. If a alone complete it the same task in 12 days how many days will b take to complete the task if he works alone
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A and B can complete work in 12 days
So A and B's 1 day work = 1/12
A alone can complete work in 15 days
So A's 1 day work = 1/15
B's 1 day work = 1/12-1/15
=(1/60)(5-4)
=(1/60)
A leaves 10 days before completion of work so work done by B alone in last 10 days.
= 10×(1/60) = 1/6
work done before that = 1-1/6 = 5/6
5/6 work done by A and B together in.
= (5/6) × 12 = 10 days
Hence, A and B work together for 10 days.
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