a and b together can complete a work in 40 days. they start work together and after 21 days b left and the wole work completed in 46 days find the time in which a alone complete 50% of work
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0
Answer:
20 days is the answer of this question
Answered by
0
Answer:
According to question
A+B complete work in 30 days
Take L.C.M of (A+B)'s time to calculate the total work Assume total work 30 units
Hence,
(A+B)'s work/day = 1 Unit/day
(A+B)'s 20 day's work = 20x1 unit/day = 20 units
Rest work = 30−20=10 units
Now, Rest work done by A in 20 days
Then one day's work of A =
10
20
=
1
2
Total work done by A in=
30
1
2
=60days
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