Question

- A and B together can complete a work in 8 days. A can do it alone in 12 days
. If B alone can do the
work in x days, obtain an equation in x. Also, find the number of days in which B alone can do the
work.

Answer 1

Step-by-step explanation:

A and B together can complete a work in 8 days. B alone complete that work in 12 days. B worked alone for 4 days. How many days A will take to complete the rest work after that?

A+B=8 days

B=12 days

So, let's take LCM of 16 and 24. That's 24.

Note: 24 unit is the total work

So, A and B do (24/8) = 3 unit work/day …(1)

And, B does (24/12) = 2 unit work/day …(2)

Equation(1)-(2)

{A+B-B=3–2=1}

A =(3–2)= 1 unit/day

Condition: B work 4 days alone and remaining work done by A.

So Work done by B= 2*4=8 units

Now, Left total work = 24–8=16 units

Remaining work done by A= 16/1=16 days

Formula: Total days required = ( left Total work)/(unit per day)

Finally answer = 16 days

plz mark as brainliest