Math, asked by arnavhisingh, 10 months ago

A and B together can do a peice of work in 10 days,but A alone can do it in 15 days .how much time would B alone take to do the same work?​

Answers

Answered by Anonymous
71

\huge\underline\mathrm{Question-}

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A and B together can do a piece of work in 10 days, but A alone can do it in 15 days. How much time would B alone take to do the same work?

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\huge\underline\mathrm{Answer-}

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B alone can complete this piece of work in 30 days.

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\huge\underline\mathrm{Explanation-}

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It is given that A and B together can do a piece of work in 10 days.

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\therefore A and B can together do \dfrac{1}{10} of work in 1 day.

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\mapsto Work of A + Work of B = \dfrac{1}{10} ⠀⠀⠀⠀⠀⠀⠀⠀⠀–eq (1)

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It is also given that A alone can do same piece of work in 15 days.

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\therefore A can do \dfrac{1}{15} of work in 1 days.

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\mapsto Work of A = \dfrac{1}{15} ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀–eq (2)

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Put the value of eq (2) in (1).

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\mapsto \dfrac{1}{15} + Work of B = \dfrac{1}{10}

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\mapsto Work of B = \dfrac{1}{10}\:-\:\dfrac{1}{15}

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\mapsto Work of B = \dfrac{3-2}{30}

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\mapsto Work of B = \dfrac{1}{30}

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So, B can do \dfrac{1}{30} of total work in 1 day.

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Hence, B can alone do a piece of work in 30 days.


Anonymous: Perfect
Answered by EliteSoul
23

Answer:

{\boxed{\tt{B\:alone\:can\:do\:in\: \: 30\:days.}}}

Step-by-step explanation:

Given that:-

  • A and B together can do the work in 10 days.
  • A alone can do it in 15 days.
  • B alone can do the work in = ? days.

_________________________

\tt A \: and \:B \: can \: do \: it \: in 10\:days. \\\therefore\tt They\:both\:can\:do\:in\: <strong>1</strong><strong> </strong>day = \frac{1}{10}\:of\: work

\tt A \:alone\:can\:do\:it \: in \: 15\:days.\\\therefore\tt A\:alone \:can\:do \: in\: <strong>1</strong><strong> </strong>day = \frac{1}{15}\:of\:work.

{\underline{\underline{\tt{According\:to\:question:}}}}

\rightarrow\tt \frac{1}{15} + \frac{1}{B} =\frac{1}{10} \\\rightarrow\tt \frac{1}{B} = \frac{1}{10} - \frac{1}{15} \\\rightarrow\tt \frac{1}{B} = \frac{3-2}{30} \\\rightarrow\tt \frac{1}{B} = \frac{1}{30} \\\rightarrow{\boxed{\tt{B\:alone\:can\:do\:in=30\:days.}}}

\therefore\bold{\underline{B\:alone\:can\:do\:the\:work\:in=30\:days.}}


Anonymous: Awesome
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