Question

A and B together can do a peice of work in 6 days.If A's one day's work is 3/2 times the one day's work of B,find in how many days,each alone can finish the work.​

Answer 1

Answer:

Step-by-step explanation:

If they can finish together in 12 days, then:

1/A + 1/B=1/12

Since A is twice efficient as B, then 1/A=2/B. So:

2/B + 1/B=1/12

3/B=1/12

B=36

A=B/2=18

A takes 18 days alone to finish; B takes 36 days alone to finish

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