Math, asked by harshininathan14, 7 months ago

A and B together can do a piece of work in 12 days and a alone can do it in 18 days in how many days can B alone do it​

Answers

Answered by ILLUSTRIOUS27
1

{ \huge\mathcal{\green{A}\blue{n}\green{S}\blue{w}\green{E}\blue{r}}}

(A+B) jointly do a piece of work in... 12 days.

(A+B) jointly do a piece of work in... 12 days.(A+B can do in 1 day.. 1/12 part of the work..(1)

(A+B) jointly do a piece of work in... 12 days.(A+B can do in 1 day.. 1/12 part of the work..(1)B alone can do the same work in 60 days

(A+B) jointly do a piece of work in... 12 days.(A+B can do in 1 day.. 1/12 part of the work..(1)B alone can do the same work in 60 daysB alone do the work in 1 day.... 1/60 part... (2)

(A+B) jointly do a piece of work in... 12 days.(A+B can do in 1 day.. 1/12 part of the work..(1)B alone can do the same work in 60 daysB alone do the work in 1 day.... 1/60 part... (2)Therefore A's daily part of work is…..

(A+B) jointly do a piece of work in... 12 days.(A+B can do in 1 day.. 1/12 part of the work..(1)B alone can do the same work in 60 daysB alone do the work in 1 day.... 1/60 part... (2)Therefore A's daily part of work is…..(1) - (2) = (1/12) - (1/60) = 4/60 or 1/15 part of the work, and hence A can do the same work in...

(A+B) jointly do a piece of work in... 12 days.(A+B can do in 1 day.. 1/12 part of the work..(1)B alone can do the same work in 60 daysB alone do the work in 1 day.... 1/60 part... (2)Therefore A's daily part of work is…..(1) - (2) = (1/12) - (1/60) = 4/60 or 1/15 part of the work, and hence A can do the same work in...Whole work... 1/(1/15) = 15 days. is the answer.

(A+B) jointly do a piece of work in... 12 days.(A+B can do in 1 day.. 1/12 part of the work..(1)B alone can do the same work in 60 daysB alone do the work in 1 day.... 1/60 part... (2)Therefore A's daily part of work is…..(1) - (2) = (1/12) - (1/60) = 4/60 or 1/15 part of the work, and hence A can do the same work in...Whole work... 1/(1/15) = 15 days. is the answer.(Thanks for asking a answer. I hope I am right!

Similar questions