A and B together can do a piece of work in 12 days, B and C together can do it in 15 days. If A is twice as good as C, in how many days A alone will do the same work?
Answers
Answered by
3
A + B = 12 days
B + C = 15 days
Efficiency - A/C = 2/1
Therefore one day work for -
A = 2u and C = 1u
Let the total work be 60u ( LCM of 12 and 15)
One day work for -
A + B = 5u - (1)
B + C = 4u - (2)
Putting the value of A=2u in eq. 1
B = 3u
Now no. of days taken by B to complete the work = 60 / 3 = 20 days
For A = 60 / 2 = 30 days
For C = 60 /1 = 60 days
B + C = 15 days
Efficiency - A/C = 2/1
Therefore one day work for -
A = 2u and C = 1u
Let the total work be 60u ( LCM of 12 and 15)
One day work for -
A + B = 5u - (1)
B + C = 4u - (2)
Putting the value of A=2u in eq. 1
B = 3u
Now no. of days taken by B to complete the work = 60 / 3 = 20 days
For A = 60 / 2 = 30 days
For C = 60 /1 = 60 days
NaYn:
answer is correct...but is there any other process
Similar questions