A and b together can do a piece of work in 12 days.if a can complete the work in 20 days
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Both A and B can complete 1/12th work in one day
So A+B=1/12 in one day
A alone can complete 1/20 th work
A=1/20 in one day
Now B alone how much work can complete
(1/20)+B=1/12
B =(1/12)-(1/20)
L.C.M of 12 and 20 is 60
So B=( (5–3)/60)
B=2/60=1/30
So alone can complete 1/30th work in one day
B alone can complete the work in 30 days
mgs93:
30
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A can do it in 20 days
1 day work of A = 1/20
A and B together in 12 days
1 day work of A+B = 1/12
1 day work of B = 1/12 - 1/20 = (5-3) / 60 = 2/60 = 30
So B can do it in 30 days
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