Math, asked by RaahulSingh, 1 year ago

A and B together can do a piece of work in 12 days
which B and C together do in 16 days. If A work for
5 days, B works for 7 days than C complete
remaining work in 13 days. In how much time B alone
does the whole work.
days.​

Answers

Answered by mdatifnasim70mp64jpe
3

According to questions,  

A worked for 5 days and  

B worked for 7 days  

If A and B Work together for 5 days  

they would complete 4×5=20 units  

remaining work = 48−20  

=28 units

Now B has to work for 2 more days and if he does it along  

with C for 2 days. Then, both would complete (3×2)=6  

units of work.  

work left = 28−6=22 units  

Now C completes in 13−2=11 days  

So, C works2211 = 2 units / day  

(efficiency) and B+Cdoes 3 units / day (efficiency)  

So B does 1 unit/day  

B will complete the whole work in 481= 48 days

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