A and b together can do a piece of work in 12 days, which b and c together can do in 16 days. After a has been working at it for 5 days and b for 7 days, c finishes it in 13 days. In how many days c alone will do the work?
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Answer:
in 6 days c will finish the work
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Work done by (A+B)'s in 1 day= 1/12
work done by (B+C)'s in 1 day= 1/16
Let C does a work in x days
Then work done by C in a day= 1/x
According to the question,
A's 5 day's work+B's 7 day's work+C's 13 day's work=1
(A+B)'s 5 day's+(B+C)'s 2 days+C's 11 day's
5/12+2/15+11/x=1
11/x=1-5/12-2/16
11/x=22/48
x=24days
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