A and b together can do a piece of work in 12 days which b and c together can do in 16 days. after a has been working at it for 5 days and b for 7 days, c finishes it in 13 days. in how many days b could finish the work
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a+b work one day = 1/12
b+ c work =1/16
c has work = x
a has been work done 5 days + b has been work done7 day + c has work done 13 day = 1
work done by a and b 5 day+ b and c done 2 day + work done by c 11 day =1
5/12+2/16+11x=1
5/12+1/8+11x=1
13/24+11x =1
11x =11/24
x = 1/24
c work in completed 24 day
b+ c work =1/16
c has work = x
a has been work done 5 days + b has been work done7 day + c has work done 13 day = 1
work done by a and b 5 day+ b and c done 2 day + work done by c 11 day =1
5/12+2/16+11x=1
5/12+1/8+11x=1
13/24+11x =1
11x =11/24
x = 1/24
c work in completed 24 day
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