A and B together can do a piece of work in 12 days while B alone can finish it in 30 days in how many days can a alone finish this work
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Answered by
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20 days
A’s 1 day’s work = \frac{1}{12}-\frac{1}{30} = \frac{5-2}{60} = \frac{3}{60} = \frac{1}{20}
So, A alone will complete the work in 20 days.
Answered by
1
Answer:
easily do
30-12=18
answer is 18days
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